Full-Wave Rectifier Output
Full-wave (no filter)
Choose bridge or center-tap, enter the AC input (RMS), frequency and diode drop.
Output
How to use this calculator
A full-wave rectifier conducts on both halves of the cycle, doubling the DC output of a half-wave. The peak is Vp = √2·Vrms, and Vdc = 2·Vp/π after accounting for two diode drops (a bridge uses two diodes per half-cycle, as does a center-tap). Choose bridge or center-tap, enter the AC RMS, frequency and diode drop, and peak, DC, RMS and ripple appear live.
What it means in a real circuit
For a 12 V RMS input the peak is ~17 V and the DC output is ~10.8 V (2·(17−1.4)/π) — roughly double a half-wave and with half the ripple frequency (120 Hz at 60 Hz mains). The PIV differs by topology: a bridge diode sees Vp, while a center-tap diode sees 2·Vp, so center-tap diodes need a higher rating. Use this for the rectifier stage of almost any mains or low-voltage power supply; add a smoothing capacitor next to tuck the ripple down.